CUET UG 2025 — General Test Arithmetic

We have two investments:

• Investment A: ₹2200 at 6% per annum (time unknown)
• Investment B: ₹1650 at 9% per annum for 10 years

The simple interest on both investments must be equal.

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For Investment B (₹1650 at 9% for 10 years):

Simple Interest $= \dfrac{\text{Principal} \times \text{Rate} \times \text{Time}}{100}$=100Principal×Rate×Time​

$$\text{SI} = \dfrac{1650 \times 9 \times 10}{100}$$SI=1001650×9×10​

$$\text{SI} = \dfrac{148500}{100}$$SI=100148500​

$$\text{SI} = ₹1485$$SI=₹1485

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For Investment A, the simple interest must also equal ₹1485.

Given:

• Principal = ₹2200
• Rate = 6%
• Simple Interest = ₹1485
• Time = ?

$$1485 = \dfrac{2200 \times 6 \times \text{Time}}{100}$$1485=1002200×6×Time​

$$1485 = \dfrac{13200 \times \text{Time}}{100}$$1485=10013200×Time​

$$1485 = 132 \times \text{Time}$$1485=132×Time

$$\text{Time} = \dfrac{1485}{132}$$Time=1321485​

$\text{Time} = 11.25$Time=11.25 years

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Converting to years and months:

$11.25$11.25 years $= 11$=11 years $+ 0.25$+0.25 years

$0.25 \times 12 = 3$0.25×12=3 months

Therefore, the time required is 11 years and 3 months.