A walks at 8 km/h and B walks at 10 km/h. They start together at the same time and travel to the same destination. A arrives 15 minutes after B.
Let the distance be d km.
Time taken by A = 8d hours
Time taken by B = 10d hours
Since A arrives 15 minutes after B, the time difference is 15 minutes.
Converting to hours: 15 minutes = 6015=41 hour
The equation becomes:
8d−10d=41
Finding LCM of 8 and 10, which is 40:
405d−4d=41
40d=41
d=440
d=10
Therefore, the distance is 10 km.