CUET UG 2025 — General Test Arithmetic

6 goats can graze a field in 50 days, or 8 sheep can graze the same field in 50 days.

Work done by 6 goats in 1 day $= \dfrac{1}{50}$=501​

Work done by 1 goat in 1 day $= \dfrac{1}{50} \div 6$=501​÷6

$$= \dfrac{1}{300}$$=3001​

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Work done by 8 sheep in 1 day $= \dfrac{1}{50}$=501​

Work done by 1 sheep in 1 day $= \dfrac{1}{50} \div 8$=501​÷8

$$= \dfrac{1}{400}$$=4001​

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Work done by 8 goats in 1 day $= 8 \times \dfrac{1}{300}$=8×3001​

$$= \dfrac{8}{300}$$=3008​

$$= \dfrac{2}{75}$$=752​

Work done by 6 sheep in 1 day $= 6 \times \dfrac{1}{400}$=6×4001​

$$= \dfrac{6}{400}$$=4006​

$$= \dfrac{3}{200}$$=2003​

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Total work done by 8 goats and 6 sheep in 1 day $= \dfrac{2}{75} + \dfrac{3}{200}$=752​+2003​

The LCM of 75 and 200 is 600.

$$= \dfrac{16}{600} + \dfrac{9}{600}$$=60016​+6009​

$$= \dfrac{25}{600}$$=60025​

$$= \dfrac{1}{24}$$=241​

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If $\dfrac{1}{24}$241​ of the field is grazed in 1 day, then the entire field is grazed in 24 days.

Therefore, 8 goats and 6 sheep can graze the field in 24 days.