CUET UG 2024 — General Test Arithmetic

Let the length of the train be $L$L meters. The total distance covered by the train while crossing the tunnel is the length of the train plus the length of the tunnel, which is $L + 350$L+350 meters.

The speed of the train is 80 km/h, which can be converted to meters per second:

$80 \text{ km/h} = \frac{80 \times 1000}{3600} = \frac{80000}{3600} \approx 22.22 \text{ m/s}$80 km/h=360080×1000​=360080000​≈22.22 m/s.

The time taken to cross the tunnel is 36 seconds. Therefore, the distance covered in that time is:

$\text{Distance} = \text{Speed} \times \text{Time} = 22.22 \times 36 \approx 800 \text{ m}$Distance=Speed×Time=22.22×36≈800 m.

Setting up the equation:

$L + 350 = 800$L+350=800.

Solving for $L$L:

$L = 800 - 350 = 450$L=800−350=450.

Thus, the length of the train is $450$450 m.