Distance = 30×6=180 km. B's speed = 180/4=45 km/h.
A's new speed = 40 km/h, time = 180/40=4.5 hr.
B's new speed = 50 km/h, time = 180/50=3.6 hr.
Difference = 4.5−3.6=0.9 hr = 54 min.
'A' rides a cycle at an average speed of 30 km/h and reaches the destination in 6 hours. B covers the same distance in 4 hours. If A increases the average speed by 10 km/h and B increases the average speed by 5 km/h What would be the difference in their time taken to reach the destination ?
Held on 19 Jun 2023 · Verified 13 Jul 2026.
24 min
30 min
27 min
54 min
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