B's 1-day work = 121. Combined A+B+C = 101+121+151=606+5+4=6015=41. Every 2 days B alone: 2×121=61; 3rd day all three: 41. Per 3-day cycle: 61+41=125. In 6 days: 1210. Remaining 122=61 needs B 2 more days. Total = 6+2=8 days.
A, B and C can do a work in 10, 12 and 15 days respectively. In how many days will the work be completed if B is assisted by both A and C on every third day ?
Held on 7 Jun 2023 · Verified 13 Jul 2026.
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