Correct Option
The correct option is 373.15 K.
Explanation
The boiling point of a liquid is the temperature at which its vapour pressure becomes equal to the external pressure. When the external pressure is 1 atmosphere (1.013 bar), the boiling temperature is specifically referred to as the normal boiling point.
Detailed Analysis
- Pressure Context: The value 1.013 bar is equivalent to 1 atmosphere (atm).
- Boiling Point at 1 atm: At this specific pressure, water boils at exactly 100°C.
- Kelvin Conversion: The relationship between the Celsius scale and the Kelvin scale is defined as:
T(K) = t(°C) + 273.15 - Calculation: Substituting the value for the boiling point of water:
373.15 K = 100 + 273.15
Thus, at a pressure of 1.013 bar, the boiling point of water is 373.15 K.
Key Takeaway: The normal boiling point of water occurs at 1 atm (1.013 bar) and corresponds to 100°C or 373.15 K.