In a dihybrid cross $RrYy \times RrYy$:
The phenotypic ratio is $9:3:3:1$
$$\text{Round Yellow (R\_Y\_)} = \frac{9}{16}, \quad \text{Wrinkled Green (rryy)} = \frac{1}{16}$$
$$\text{Ratio} = 9:1$$
Verified 30 May 2026.
In a dihybrid cross between $RrYy \times RrYy$, the phenotypic ratio of round yellow to wrinkled green is:
$9:1$
$3:1$
$9:3$
$1:1$
In a dihybrid cross $RrYy \times RrYy$:
The phenotypic ratio is $9:3:3:1$
$$\text{Round Yellow (R\_Y\_)} = \frac{9}{16}, \quad \text{Wrinkled Green (rryy)} = \frac{1}{16}$$
$$\text{Ratio} = 9:1$$
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In a dihybrid cross, the phenotypic ratio in F₂ generation is:
Which of the following is a sex-linked recessive disorder?
In Mendel's monohybrid cross, the phenotypic ratio in F₂ generation is:
The phenotypic ratio of a monohybrid cross in F₂ generation is:
What fraction of the F₂ plants with round seeds will be heterozygous for seed shape?