Midpoint $= \frac{\vec{A} + \vec{B}}{2} = \frac{(2+4)\hat{i} + (3+1)\hat{j} + (1-2)\hat{k}}{2} = 3\hat{i} + 2\hat{j} - \frac{\hat{k}}{2}$
Back to JEE Main 2025 Vectors & 3D Geometry
JEE Main 2025 — Mathematics Vectors & 3D Geometry
easy
mcq
2025
Official previous-year question
Verified 30 May 2026.
Question
The position vectors of points $A$ and $B$ are $2\hat{i} + 3\hat{j} + \hat{k}$ and $4\hat{i} + \hat{j} - 2\hat{k}$. The position vector of the midpoint of $AB$ is:
Options
- A
$3\hat{i} + 2\hat{j} - \frac{\hat{k}}{2}$
- B
$6\hat{i} + 4\hat{j} - \hat{k}$
- C
$\hat{i} + \hat{j} + \frac{3\hat{k}}{2}$
- D
$3\hat{i} + 2\hat{j} + \frac{\hat{k}}{2}$
Solution
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