∣(a×b×c)∣=∣a×b∣∣c∣23∣c−a∣=22∣c∣2+∣a∣2−2c⋅a=8∣z∣2+38−12∣z∣=8∣z∣2−12∣z∣+30=0∣z∣=212±144−120=212±26 ∣z∣=6+6a×b=ℓ^61j^11k^−10ℓ^−j^+5k^∣a×b∣=27∣(a×b)×z∣=27(6+6)2329(6+6)
Let a=6i^+j^−k^ and b=i^+j^. If c is a is vector such that ∣c∣≥6,a⋅c=6∣c∣,∣c−a∣=22 and the angle between a×b and c is 60∘, then ∣(a×b)×c∣ is equal to:
Held on 6 Apr 2024 · Verified 6 Jul 2026.
29(6−6)
236
29(6+6)
233
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Work through every JEE Main Vectors & 3D Geometry PYQ, year by year.