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Let ABC be a triangle such that BC= a, CA= b, AB= ,| a|=6√2,| b|=2√3 and b· =12 Consider the statements : (S1): |( a× b)+( × b)|-| |=6(2√2-1) (S2):…

JEE Main 2022 — Mathematics Vectors & 3D Geometry

2022mcqmedium

Let ABCABCABC be a triangle such that BC⃗=a⃗,CA⃗=b⃗\vec{BC}=\vec{a},\vec{CA}=\vec{b}BC=a,CA=b, AB⃗=c⃗,∣a⃗∣=62,∣b⃗∣=23\vec{AB}=\vec{c},|\vec{a}|=6\sqrt{2},|\vec{b}|=2\sqrt{3}AB=c,∣a∣=62​,∣b∣=23​ and b⃗⋅c⃗=12\vec{b}\cdot \vec{c}=12b⋅c=12 Consider the statements :

(S1)(S1)(S1): ∣(a⃗×b⃗)+(c⃗×b⃗)∣−∣c⃗∣=6(22−1)|(\vec{a}\times \vec{b})+(\vec{c}\times \vec{b})|-|\vec{c}|=6(2\sqrt{2}-1)∣(a×b)+(c×b)∣−∣c∣=6(22​−1)

(S2)(S2)(S2): ∠ABC=cos−1(23)\angle ABC={\mathrm{cos}}^{-1}(\sqrt{\frac{2}{3}})∠ABC=cos−1(32​​). Then

Official previous-year question

Held on 25 Jul 2022 · Verified 6 Jul 2026.

Options

  1. A

    both (S1)(S1)(S1) and (S2)(S2)(S2)are true

  2. B

    only (S1)(S1)(S1) is true

  3. C

    only (S2)(S2)(S2) is true

  4. D

    both (S1)(S1)(S1) and (S2)(S2)(S2) are false

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