Let the given diagonals be d1 and d2 , then
d1×d2=∣i^83j^−64k^0−12∣
=72i^−(−96)j^+50k^
∣d1×d2∣=722+(−96)2+(50)2=5184+9216+2500
∣d2×d2∣=16900=130
Area=21∣d1×d2∣=21×130
=65
The area (in sq. units) of the parallelogram whose diagonals are along the vectors 8i^−6j^ and 3i^+4j^−12k^, is:
Held on 8 Apr 2017 · Verified 6 Jul 2026.
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