ax+2by+3b+λ(bx−2ay−3a)=0⇒(a+bλ)x+(2b−2aλ)y+3b−3λa=0a+bλ=0⇒λ=−a/b⇒ax+2by+3b−ba(bx−2ay−3a)=0⇒ax+2by+3b−ax+b2a2y+b3a2=0y(2b+b2a2)+3b+b3a2=0y(b2b2+2a2)=−(b3b2+3a2)y=2(b2+a2)−3(a2+b2)=2−3 y=−23 so it is 3/2 units below x-axis.
JEE Main 2005 — Mathematics Vectors & 3D Geometry
The line parallel to the x-axis and passing through the intersection of the lines ax + 2by+3b=0 and bx−2ay−3a=0, where (a,b)=(0,0) is
Held on 30 Apr 2005 · Verified 6 Jul 2026.
below the x-axis at a distance of 23 from it
below the x-axis at a distance of 32 from it
above the x-axis at a distance of −3 from it
above the x-axis at a distance of 32 from it
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