Any point on the line 1x=1y+a=1z=t1 (say) is (t1,t1−a,t1) and any point on the line 2x+a=1y=1z=t2( say ) is (2t2−a,t2,t2). Now direction cosine of the lines intersecting the above lines is proportional to (2t2−a−t1,t2−t1+a,t2−t1). Hence 2t2−a−t1=2k,t2−t1+a=k and t2−t1=2k On solving these, we get t1=3a,t2=a. Hence points are (3a,2a,3a) and (a,a,a)
A line with direction cosines proportional to 2,1,2 meets each of the lines x=y+a=z and x+a=2 y=2 z. The co-ordinates of each of the point of…
JEE Main 2004 — Mathematics Vectors & 3D Geometry
A line with direction cosines proportional to 2,1,2 meets each of the lines x=y+a=z and x+a=2y=2z. The co-ordinates of each of the point of intersection are given by
Held on 30 Apr 2004 · Verified 6 Jul 2026.
Options
- A
(3a,3a,3a),(a,a,a)
- B
(3a,2a,3a),(a,a,a)
- C
(3a,2a,3a),(a,a,2a)
- D
(2a,3a,3a),(2a,a,a)
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