median =ℓ+(f2N−F)×h=12+(122N−18)×6=14⇒(122 N−18)×6=22 N−18=4⇒ N=44
Marks obtains by all the students of class 12 are presented in a freqency distribution with classes of equal width. Let the median of this grouped data be 14 with median class interval 12-18 and median class frequency 12 . If the number of students whose marks are less than 12 is 18 , then the total number of students is
Held on 23 Jan 2025 · Verified 6 Jul 2026.
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