E1:BagB1 is selected $\begin{array}{lll}
B_1 & B_2 & B_3 \
\text { 6W4B } & 4 \mathrm{W} 6 \mathrm{B} & 5 \mathrm{W} 5 \mathrm{B}
\end{array}\mathrm{E}_2:bag\mathrm{B}_2isselectedE_3: B a g B_3isselectedA:DrawnballiswhiteWehavetofind\mathrm{P}\left(\frac{\mathrm{E}_2}{\mathrm{~A}}\right)P\left(\frac{E_2}{A}\right)=\frac{P\left(E_2\right) P\left(\frac{A}{E_2}\right)}{P\left(E_1\right) P\left(\frac{A}{E_1}\right)+P\left(E_2\right) P\left(\frac{A}{E_2}\right)+P\left(E_3\right) P\left(\frac{A}{E_3}\right)}\begin{aligned} & =\frac{\frac{1}{3} \times \frac{4}{10}}{\frac{1}{3} \times \frac{6}{10}+\frac{1}{3} \times \frac{4}{10}+\frac{1}{3} \times \frac{5}{10}} \ & =\frac{4}{15}\end{aligned}$