$\begin{array}{|c|c|c|c|c|c|c|}
\hline \mathrm{x} & \mathrm{C} & 2 \mathrm{C} & 3 \mathrm{C} & 4 \mathrm{C} & 5 \mathrm{C} & 6 \mathrm{C} \
\hline \mathrm{f} & 2 & 1 & 1 & 1 & 1 & 1 \
\hline
\end{array}\bar{x}=\frac{(2+2+3+4+5+6) C}{7}=\frac{22 C}{7}\begin{aligned} & \operatorname{Var}(x)=\frac{\mathrm{c}^2\left(2+2^2+3^2+4^2+5^2+6^2\right)}{7} \ & -\left(\frac{22 \mathrm{c}}{7}\right)^2 \ & =\frac{92 \mathrm{c}^2}{7}-\mathrm{c}^2 \times \frac{484}{49} \ & =\frac{(644-484) \mathrm{c}^2}{49}=\frac{160 \mathrm{c}^2}{49} \ & 160=\frac{160 \times \mathrm{c}^2}{49} \Rightarrow \mathrm{c}=7\end{aligned}$