Given:
P(Aˉ∩B)+P(A∩Bˉ)=1−k
P(Aˉ∩C)+P(A∩Cˉ)=1−k
P(Bˉ∩C)+P(B∩Cˉ)=1−2k
P(A∩B∩C)=k2
Now,
P(A)+P(B)−2P(A∩B)=1−k…(i)
P(B)+P(C)−2P(B∩C)=1−2k…(ii)
P(C)+P(A)−2P(A∩C)=1−k…(iii)
Adding (i),(ii)&(iii), we get
P(A)+P(B)+P(C)−P(A∩B)−P(B∩C)−P(C∩A)=2−4k+3
Now,
P(A∪B∪C)=P(A)+P(B)+P(C)−P(A∩B)−P(B∩C)−P(C∩A)+P(A∩B∩C)
⇒P(A∪B∪C)=2−4k+3+k2
⇒P(A∪B∪C)=22k2−4k+3
⇒P(A∪B∪C)=22(k−1)2+1
⇒P(A∪B∪C)=(k−1)2+21
⇒P(A∪B∪C)>21