σ2=n1+n2n1σ12+n2σ22+(n1+n2)n1n2(xˉ1−xˉ2)2
n1=10,n2=n,σ12=2,σ22=1
xˉ1=2,xˉ2=3,σ2=917
917=n+1010×2+n+(n+10)210n(3−2)2
⇒917=(n+10)2(n+20)(n+10)+10n
⇒17n2+1700+340n=90n+9(n2+30n+200)
⇒8n2−20n−100=0
2n2−5n−25=0
⇒(2n+5)(n−5)=0⇒n=(Rejected)↓2−5,5
Hence n=5