20 Boys, 30 Girls
σB2=2,XˉB=12σG2=2
XˉG=3050×15−20×12=30510=17=μ
Variance of 50 condidates
σ2=20+3020σB2+30σG2+(20+30)220⋅30(XˉB−XˉG)2
=5020×2+30×2+2500600(25)=8
μ+σ2=17+8=25
An online exam is attempted by 50 candidates out of which 20 are boys. The average marks obtained by boys is 12 with a variance 2. The variance of marks obtained by 30 girls is also 2. The average marks of all 50 candidates is 15. If μ is the average marks of girls and σ2 is the variance of marks of 50 candidates, then μ+σ2 is equal to
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