Given mean of 6 observations is 48⇒641+45+54+57+43+x=48
⇒x=48
Now variance σ2=n∑(x−x)2
=672+32+62+92+52+02
=3100
Hence standard deviation =310.
JEE Main 2019 — Mathematics Probability & Statistics
A student scores the following marks in five tests: 45,54,41,57,43. His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is:
Held on 8 Apr 2019 · Verified 6 Jul 2026.
310
3100
310
3100
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