5x+y+1+2+6=5
⇒x+y=16
Now 12.4=5(16+9+1+(x−5)2+(y−5)2)
⇒62=26+(x−5)2+(y−5)2
⇒36=(x−5)2+(y−5)2
Shifting of the origin to (5,5) the equations will become
62=x2+y2 and x+y=6
Solving them and again will get the x=0 or y=0.
If x=0⇒y=6 or
If y=0⇒x=6.
But by shifting the origin back to original position, we get x=0+5=5&y=6+5=11
(or)
x=6+5=11&y=0+5=5
Hence, the values of the remaining two are 5,11.