Variance of a set of n numbers (x1,x2...xi,...xn) is given
σ2=n1Σi=1n(xi−xˉ)2, where xˉ is the average of the numbers.
We want the variance of (2,4,6,8.....48,50,52,.....98,100)
Here xˉ=51.
(xi−xˉ) will be symmetric about 51,
∴σ2=502(12+32+52+...492)
Now, 12+32+52+...+492=(12+22+32+...+492+502)−(22+42+62+...+482+502)
=6(50)(51)(101)−4(12+22+)
=6(50)(51)(101)−64(25)(26)(51)
=42925−22100
=20825
∴σ2=502×20825=833