We know that P(E/A)=P(A)P(E∩A)
⇒P(E∩A)=P(E/A)⋅P(A)...(i)
Also, P(A/E)=P(E)P(E∩A)
⇒P(E∩A)=P(A/E)⋅P(E)(ii)
From the equations (i) and (ii), we get
P(E/A)⋅P(A)=P(A/E)⋅P(E)
Now, since 0<P(A)≤1
⇒P(E/A)≥P(A/E)⋅P(E)
Again, we have P(A/E)=P(E)P(E∩A)
⇒P(A/E)⋅P(E)=P(E∩A)
Now, since 0<P(E)≤1
P(A/E)≥P(A∩E)
⇒Both the statements are true.