Since 0<y<x<2y ∴y>2x⇒x−y<2x∴x−y<y<x<2x+y Hence median =2y+x=10 ⇒x+y=20 And range =(2x+y)−(x−y)=x+2y But range =28 ∴x+2y=28 From equations (i) and (ii), x=12,y=8∴ Mean =4(x−y)+y+x+(2x+y)=44x+y =x+4y=12+48=14
If the median and the range of four numbers {x,y,2x+y,x−y}, where 0<y<x<2y, are 10 and 28 respectively, then the mean of the numbers is :
Held on 23 Apr 2013 · Verified 6 Jul 2026.
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