η = 1 - T₂/T₁ = 1 - 300/600 = 0.5 = 50%
Back to JEE Advanced 2025 Thermodynamics
JEE Advanced 2025 — Physics Thermodynamics
easy
mcq
2025
Official previous-year question
Verified 30 May 2026.
Question
A Carnot engine operates between temperatures 600 K and 300 K. Its efficiency is:
Options
- A
25%
- B
50%
- C
75%
- D
100%
Solution
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