Match List-I with List-II
| List-I | List-II |
|---|---|
| (A) Equations of line through (5,−4,6) with direction ratios 3,7,2 | (I) 5x+3=−4y+7=6z+2 |
| (B) Equations of line through (3,7,2) with direction ratios 5,−4,6 | (II) 5x−3=−4y−7=6z−2 |
| (C) Equations of line through (−5,4,−6) with direction ratios 3,7,2 | (III) 3x−5=7y+4=2z−6 |
| (D) Equations of line through (−3,−7,−2) with direction ratios 5,−4,6 | (IV) 3x+5=7y−4=2z+6 |
Choose the correct answer from the options given below:
Held on 22 May 2025 · Verified 13 Jul 2026.
(A) - (III), (B) - (II), (C) - (IV), (D) - (I)
(A) - (III), (B) - (I), (C) - (I), (D) - (IV)
(A) - (IV), (B) - (I), (C) - (III), (D) - (II)
(A) - (I), (B) - (IV), (C) - (II), (D) - (III)
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
The shortest distance between the following lines: $\vec{r} = (\hat{i} + \hat{j} - \hat{k}) + s(2\hat{i} + \hat{j} + \hat{k})$ $\vec{r} = (\hat{i} + \hat{j} + 2\hat{k}) + t(4\hat{i} + 2\hat{j} + 2\hat{k})$, where s and t are scalars, is:
The angle between the line $2x = 3y = z$ and $x$- axis is:
The angle at which the line, $\frac{x-1}{0} = \frac{2-y}{-1} = \frac{2z-3}{-2}$ is inclined with the positive direction of z-axis is
$\sin^{-1}(\cos\frac{3\pi}{5})$ equals
If lines $\frac{x+5}{5\lambda+2} = \frac{4-2y}{10} = \frac{1-3z}{-3}$ and $\frac{x-2}{1} = \frac{1+2y}{4\lambda} = \frac{2+z}{3}$ are perpendicular, than value of '$\lambda$' is
Work through every CUET UG Geometry PYQ, year by year.