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Let the equation of lines be as L_1: r_1 = a_1 + λ b_1 and L_2: r_2 = a_2 + λ b_2 such that a_1 - a_2 = 2 i + 4 j + 4 k and b_1 × b_2 = 8 i - 4 k.…

CUET UG 2025 — Mathematics Geometry

2025mcqmedium

Let the equation of lines be as L1:r1⃗=a1⃗+λb1⃗L_1: \vec{r_1} = \vec{a_1} + \lambda\vec{b_1}L1​:r1​​=a1​​+λb1​​ and L2:r2⃗=a2⃗+λb2⃗L_2: \vec{r_2} = \vec{a_2} + \lambda\vec{b_2}L2​:r2​​=a2​​+λb2​​ such that a1⃗−a2⃗=2i^+4j^+4k^\vec{a_1} - \vec{a_2} = 2\hat{i} + 4\hat{j} + 4\hat{k}a1​​−a2​​=2i^+4j^​+4k^ and b1⃗×b2⃗=8i^−4k^\vec{b_1} \times \vec{b_2} = 8\hat{i} - 4\hat{k}b1​​×b2​​=8i^−4k^. Then the shortest distance between L1L_1L1​ and L2L_2L2​ is

Official previous-year question

Held on 29 May 2025 · Verified 13 Jul 2026.

Options

  1. A

    202020

  2. B

    444

  3. C

    000

  4. D

    232\sqrt{3}23​

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