Parametrize: (t−5,4t−3,−9t+6). Vector from this to (2,4,−1): (7−t,7−4t,−7+9t). Perpendicular to (1,4,−9): (7−t)+4(7−4t)−9(−7+9t)=0⇒7−t+28−16t+63−81t=0⇒98−98t=0, t=1. Foot: (−4,1,−3).
The foot of perpendicular from point (2, 4, -1) on the line x+5 1 = y+3 4 = z-6 -9 is :
CUET UG 2022 — Mathematics Geometry
2022mcqmedium
The foot of perpendicular from point (2,4,−1) on the line 1x+5=4y+3=−9z−6 is :
Official previous-year question
Held on 17 Aug 2022 · Verified 13 Jul 2026.
Options
- A
(−4,1,−3)
- B
(4,1,−3)
- C
(4,1,3)
- D
(4,−1,3)
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