Parallel plane: 3x+4y−12z=k. At (1,1,−1): 3+4+12=19. So equation is 3x+4y−12z=19.
The equation of the plane, parallel to the plane 3x+4y−12z=3 and passes through (1,1,−1), is :
Held on 17 Aug 2022 · Verified 13 Jul 2026.
3x+4y−12z=0
3x+4y+12z=3
3x+4y−12z=19
3x+4y−12z=22
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