sin−1(cosx)=sin−1(sin(2π−x))=2π−x when 2π−x∈[−2π,2π], i.e., 0≤x≤π.
sin−1(cosx)=2π−x is valid for :
Held on 23 Aug 2022 · Verified 13 Jul 2026.
−π≤x≤0
0≤x≤π
−2π≤x≤2π
−4π≤x≤43π
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