∫ex[f(x)+f′(x)]dx=exf(x)+c. Here f(x)=secx and f′(x)=secxtanx, so the integral =exsecx+c.
The probability distribution of a random variable X is given below : | X | 0 | 1 | 2 | 3 | 4 | |---|---|---|---|---|---| | P(X) | 0.1 | 0.25 | 0.3 |…
CUET UG 2023 — Mathematics Applied-Mathematics
2023mcqmedium
The probability distribution of a random variable X is given below :
| X | 0 | 1 | 2 | 3 | 4 |
|---|---|---|---|---|---|
| P(X) | 0.1 | 0.25 | 0.3 | 0.2 | 0.15 |
Then, Var(2X) is :
Official previous-year question
Held on 30 May 2023 · Verified 13 Jul 2026.
Options
- A
0.368751
- B
0.361875
- C
0.36758
- D
0.369822
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