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Let f : R → R be defined such that f(x) = 16x^2 - 16x + 12 (A) Maximum value of f(x) is 8 (B) Minimum value of f(x) is 8 (C) Minimum value of f(x) is…

CUET UG 2023 — Mathematics Applied-Mathematics

2023mcqeasy

Let f:R→Rf : R \to Rf:R→R be defined such that f(x)=16x2−16x+12f(x) = 16x^2 - 16x + 12f(x)=16x2−16x+12
(A) Maximum value of f(x)f(x)f(x) is 8
(B) Minimum value of f(x)f(x)f(x) is 8
(C) Minimum value of f(x)f(x)f(x) is 16
(D) No maximum value of f(x)f(x)f(x)
Choose the correct answer from the options given below :

Official previous-year question

Held on 30 May 2023 · Verified 13 Jul 2026.

Options

  1. A

    (A), (C) Only

  2. B

    (B), (D) Only

  3. C

    (A), (B), (C) Only

  4. D

    (A), (B) Only

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