From (x+1)ey=1: ey=x+11, so y=−ln(x+1).
dxdy=−x+11, so (dxdy)2=(x+1)21.
dx2d2y=(x+1)21.
Therefore dx2d2y=(dxdy)2.
If (x+1)ey=1 , then :
Held on 7 Jun 2023 · Verified 13 Jul 2026.
dx2d2y=y2
dx2d2y=(dxdy)2
dx2d2y=−y2
dx2d2y=dxdy
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