f′(x)=3x2−6x+4=3(x−1)2+1, which is always positive. So f is increasing on the entire real line R.
The interval in which where the function f(x)=x3−3x2+4x+1,x∈R is increasing in, is :
Held on 11 Aug 2022 · Verified 13 Jul 2026.
[2,3]
[-2,4]
[0,2]
R
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