Simplify 360x+240y≤5760 to 3x+2y≤48. Intersection of x+y=20 and 3x+2y=48 gives (8,12). Corner points: (0,0),(16,0),(8,12),(0,20).
Given a linear programming problem, Max Z = 22x + 18y, Subject to constraints x + y ≤ 20, 360x + 240y ≤ 5760, x ≥ 0, y ≥ 0. Its corner points are :
CUET UG 2022 — Mathematics Applied-Mathematics
2022mcqmedium
Given a linear programming problem,
Max Z=22x+18y, Subject to constraints
x+y≤20,360x+240y≤5760,x≥0,y≥0. Its corner points are :
Official previous-year question
Held on 11 Aug 2022 · Verified 13 Jul 2026.
Options
- A
(0,0),(16,0),(8,12),(0,20)
- B
(0,0),(0,0),(12,0),(0,12)
- C
(16,0),(0,16),(0,20),(8,0)
- D
(1,1),(16,0),(8,12),(0,20)
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