Let the two digits be a and b.
From the problem:
a+b=14 ... (Equation 1)
a−b=2 ... (Equation 2)
Adding Equation 1 and Equation 2:
a+b=14
a−b=2
2a=16
a=8
Using Equation 1:
8+b=14
b=14−8
b=6
The two digits are 8 and 6.
Product =8×6
=48
Therefore, the product of the two digits is 48.