CUET UG 2025 — General Test Quantitative Reasoning

Let Sunita's present age $= S$=S

Let Reena's present age $= R$=R

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Reena is twice as old as Sunita:

$$R = 2S$$R=2S

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Three years ago, Reena's age was $R - 3$R−3

Three years ago, Sunita's age was $S - 3$S−3

At that time, Reena was three times as old as Sunita:

$$R - 3 = 3(S - 3)$$R−3=3(S−3)

$$R - 3 = 3S - 9$$R−3=3S−9

$$R = 3S - 6$$R=3S−6

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From the two equations:

$$R = 2S$$R=2S

$$R = 3S - 6$$R=3S−6

Setting them equal:

$$2S = 3S - 6$$2S=3S−6

$$2S - 3S = -6$$2S−3S=−6

$$-S = -6$$−S=−6

$$S = 6$$S=6

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Sunita's present age is $6$6 years.

Using $R = 2S$R=2S:

$$R = 2 \times 6$$R=2×6

$$R = 12$$R=12

Therefore, Reena's present age is $12$12 years.