CUET UG 2025 — General Test Quantitative Reasoning

The word DELETE has 6 letters: D-E-L-E-T-E

Counting each letter:

• D appears 1 time
• E appears 3 times
• L appears 1 time
• T appears 1 time

The letter E repeats 3 times.

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When letters repeat, the number of distinct arrangements is:

Number of arrangements = $\dfrac{6!}{3!}$3!6!​

where $6!$6! accounts for total letters and $3!$3! accounts for the repetition of E.

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$$6! = 6 \times 5 \times 4 \times 3 \times 2 \times 1$$6!=6×5×4×3×2×1

$$6! = 720$$6!=720

$$3! = 3 \times 2 \times 1$$3!=3×2×1

$$3! = 6$$3!=6

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Number of arrangements = $\dfrac{720}{6}$6720​

Number of arrangements = $120$120

Therefore, the letters of 'DELETE' can be arranged in 120 different ways.