Given:
a+b+c=14
a2+b2+c2=96
Using the algebraic identity:
(a+b+c)2=a2+b2+c2+2(ab+bc+ca)
Substituting the given values:
(14)2=96+2(ab+bc+ca)
196=96+2(ab+bc+ca)
196−96=2(ab+bc+ca)
100=2(ab+bc+ca)
ab+bc+ca=2100
ab+bc+ca=50
Therefore, (ab+bc+ca)=50
If : a + b + c = 14 and a^2 + b^2 + c^2 = 96, then (ab + bc + ca) is
CUET UG 2025 — General Test Quantitative Reasoning
2025mcqeasy
If : a+b+c=14 and a2+b2+c2=96, then (ab+bc+ca) is
Official previous-year question
Held on 15 May 2025 · Verified 13 Jul 2026.
Options
- A
96
- B
50
- C
14
- D
82
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