For a 3-digit number, the first digit cannot be 0, giving 9 choices. The second digit has 10 choices (0-9). For the number to be even, the last digit must be 0, 2, 4, 6, or 8 - giving 5 choices. Total = 9×10×5=450.
How many 3 digit even numbers can be formed from the digits (0 - 9) if repetition of digits are allowed?
Held on 15 Jun 2023 · Verified 13 Jul 2026.
350
400
450
1000
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