P(multiple of 3 in first throw) = 2/6 = 1/3 (outcomes 3, 6).
P(odd in second throw) = 3/6 = 1/2 (outcomes 1, 3, 5).
Since throws are independent, combined probability = 31×21=61.
A dice is thrown twice. Find the probability of getting an odd number in the second throw and a multiple of 3 in the first throw.
Held on 30 May 2023 · Verified 13 Jul 2026.
21
31
61
91
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