CUET UG 2025 — General Test Logical Reasoning

Given that 1st January 2006 was a Sunday, we need to find the day on 2nd January 2010.

The total time span needs to be calculated from 1st January 2006 to 2nd January 2010.

---

Counting the number of days in each year:

Year 2006: 365 days (not a leap year)

Year 2007: 365 days (not a leap year)

Year 2008: 366 days (leap year, divisible by 4)

Year 2009: 365 days (not a leap year)

From 1st January 2010 to 2nd January 2010: 1 day

Total days $= 365 + 365 + 366 + 365 + 1$=365+365+366+365+1

Total days $= 1462$=1462

---

To find the day of the week, we calculate the number of complete weeks and remaining days:

$1462 \div 7 = 208$1462÷7=208 remainder $6$6

This means $1462 = 7 \times 208 + 6$1462=7×208+6

The remainder is 6 days.

---

Starting from Sunday (1st January 2006) and moving forward 6 days:

Sunday $\rightarrow$→ Monday $\rightarrow$→ Tuesday $\rightarrow$→ Wednesday $\rightarrow$→ Thursday $\rightarrow$→ Friday $\rightarrow$→ Saturday

Therefore, 2nd January 2010 was a Saturday.

The correct answer is Option 1: Saturday.