CUET UG 2025 — General Test Logical Reasoning

To identify the odd one out, we need to examine the properties of each number.

Checking if each number is prime:

For 191:
Testing divisibility by primes up to $\sqrt{191} \approx 13.8$191​≈13.8
191 is not divisible by 2, 3, 5, 7, 11, or 13
Therefore, 191 is prime.

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For 149:
Testing divisibility by primes up to $\sqrt{149} \approx 12.2$149​≈12.2
149 is not divisible by 2, 3, 5, 7, or 11
Therefore, 149 is prime.

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For 273:
Testing divisibility: $273 \div 3 = 91$273÷3=91

$$273 = 3 \times 91$$273=3×91

$$273 = 3 \times 7 \times 13$$273=3×7×13

Therefore, 273 is composite (not prime).

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For 233:
Testing divisibility by primes up to $\sqrt{233} \approx 15.3$233​≈15.3
233 is not divisible by 2, 3, 5, 7, 11, or 13
Therefore, 233 is prime.

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The numbers 191, 149, and 233 are all prime numbers.

The number 273 is a composite number.

Therefore, 273 is the odd one out.