The observer is 2 m tall and stands 24√3 m away from the building. The angle of elevation to the top of the building is 30°.
The angle of elevation is measured from the observer's eye level, not from the ground. Let the total height of the building be H meters.
The height of the building above eye level is (H−2) meters.
Using the tangent ratio:
tan(30°)=adjacentopposite
tan(30°)=243H−2
Since tan(30°)=31:
31=243H−2
Cross multiplying:
1×243=(H−2)×3
243=(H−2)×3
Dividing both sides by 3:
24=H−2
H=26
Therefore, the height of the building is 26 m.