JEE Advanced 2026 — Physics Mechanics
A particle moves along the $x$-axis with acceleration $a = -\omega^2 x$. If at $t = 0$, $x = A$ and $v = 0$, then $x(t)$ is:
Verified 30 May 2026.
$A\cos(\omega t)$
$A\sin(\omega t)$
$Ae^{-\omega t}$
$A\cos(\omega t) + A\sin(\omega t)$
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