Statistics & Applications PYQ — Page 9
CUET UG Mathematics — Statistics & Applications previous year questions with solutions.
All Statistics & Applications Questions (254)
At what rate of interest will the present value of a perpetuity of ₹ 500 payable at the end of every 6 months be ₹ 20,000?
At what rate of interest will the present value of a perpetuity of Rs. 1000 payable at the end of every six months be Rs. 20000?
At 6% converted quarterly, the present value of a perpetuity of ₹ 900 payable at the end of each quarter is:
Assuming the same rate of change continues for the following data: | Year (x) | 2019 | 2020 | 2021 | 2022 | 2023 | |---|---|---|---|---|---| | Profit(in Percentage) (y) | 38 | 40 | 65 | 72 | 69 | The equation of the straight line trend using the least square method is:
As per the graph given below:  Match List-I with List-II | List-I | List-II | |---|---| | (Function/Area/point) | (Representation) | | (A) Consumers Surplus | (I) y=g(x) | | (B) Supply function | (II) v | | (C) Demand function | (III) s | | (D) Equilibrium point | (IV) y=f(x) | Choose the correct answer from the options given below:
Arrange the following as per statistical inferences: (A) Data Analysis (B) Population (C) Making Inferences (D) Data Collection Choose the correct answer from the options given below:
Anush takes a loan of ₹ 150000 @ 16% annual interest for 5 years. His EMI (Equally Monthly Installment) on monthly basis under flat rate system is:
Anshu takes a personal loan of ₹10,00,000 at the rate of 12% per annum for 2 years, then the EMI by using flat rate method is
Anisha invested Rs.20000 in a mutual fund in the year 2016, which increased to Rs.36000 in the year 2024. The percentage compounded annual growth rate(CAGR) of her investment is: (Given: $(1.8)^{1/8} = 1.076$)
An investment of ₹ 3,00,000 becomes ₹ 4,50,000 in 5 years, then the compound annual growth rate (CAGR) is equal to: [Given that: $(1.5)^{1/5} = 1.084$]
An automobile dealer wishes to buy four luxury cars of different brands given in the table below with some down payment and balance in equal monthly installments (EMI) for 10 years. The bank charges 9% interest per annum compounded monthly. $\left( {Given } \frac{0.0075 \times(1.0075)^{120}}{(1.0075)^{120}-1} = 0.01266\right)$ | Luxury Car | Price of the Car (in Rs.) | Down payment (in Rs.) | |---|---|---| | P | 25,00,000 | 5,00,000 | | Q | 35,00,000 | 12,00,000 | | R | 45,00,000 | 15,00,000 | | S | 42,00,000 | 15,00,000 | Match List-I with List-II | List-I | List-II | |---|---| | Luxury Car | EMI (in Rs.) | | (A) P | (I) 34,182 | | (B) Q | (II) 37,980 | | (C) R | (III) 29,118 | | (D) S | (IV) 25,320 | Choose the correct answer from the options given below:
An annuity in which the periodic payment begin on a fixed date and continue forever is called
Ajesh purchased a printer ₹ 15,000. The printer is estimated to have a scrap value of ₹ 3,000 after a span of 6 years. Then the book value of the printer at the end of 3 years will be:-
Ajesh has set up a sinking fund in order to have ₹ 10,00,000 after 10 years for his son's education. The amount should be set aside at the end of every 6 months into an account paying 5% per annum compounded half yearly is: [given $(1.025)^{20} = 1.6386$]
A T.V. panel costing Rs 18000 has a useful life of 12 years. If the annual depreciation is Rs 1000, then its scrap value by linear method is:
A trust invites a deposit of lumpsum amount from individual so that annual scholarship of Rs.5000 is paid. Rate of interest is 5% per annum. If the scholarship is to start at the end of this year then the amount needed to deposit to Trust is:
A startup company invested ₹ 5,00,000 in shares for 4 years. The value of the investment was ₹ 5,50,000 at the end of first year, ₹ 5,25,000 at the end of third year, and on maturity, the final value stood ₹ 6,25,000. The CAGR on the investment will be :- [Given : $(1.25)^{\frac{1}{4}} = 1.06$]
A specific characteristic of a sample is known as a
A sofa set costing ₹ 36000 has a useful life of 10 years. If the annual depreciation is ₹ 3000, then the scrap value by linear method is:
A small start-up started making wafers and distributing them to the retailers. After a week, average sales per week were found to be 150 packets. So, to increase the sales, a strategy was used to change the packaging and add a chocolate worth Rs. 5 as a free gift with the pack. After this, a sample of 17 shops was taken, which showed that sales went up with mean 165 and a standard deviation of 25. Check whether the strategy was effective @5%, level of significance ? [Given $ t_{16} (0.05) =2.12$]
A random sample of size 16 has 53 as mean. The sum of the squares of the deviations taken from mean is 150. If the population mean is 56 then the value of t-test statistic is:
A random sample of 100 individuals provides 25 positive responses. Then the point estimate of the population proportion with "positive" responses is:
A piece of machinery is bought for Rs. 50,000. In the first year, it depreciates by 15%, and in each subsequent year, the depreciation rate increases by 5% from the previous year. The value of machinery after 3 years will be:
A person wishes to purchase a house for ₹ 39,65,000 with a down payment of ₹ 5,00,000 and balance in equal monthly installments (EMI) for 25 years. If bank charges 6% per annum (compounded monthly), then EMI on reducing balance payment method is: [Given $(1.005)^{300} = 4.465$]