Let the son's present age be x years and the father's present age be y years.
The father's present age is 4 years more than double the son's age:
y=2x+4 ... (1)
After 10 years, the father's age will be y+10 and the son's age will be x+10.
The father's age will be 30 years more than the son's age:
y+10=(x+10)+30
y+10=x+40
y=x+30 ... (2)
From equations (1) and (2):
2x+4=x+30
2x−x=30−4
x=26
The son's present age is 26 years.
Substituting x=26 in equation (1):
y=2(26)+4
y=52+4
y=56
Therefore, the present age of the father is 56 years.