The first term a=25, last term l=180, and sum S=1025.
For an arithmetic progression, the sum of all terms is:
S=2n×(a+l)
where n is the number of terms.
Substituting the known values:
1025=2n×(25+180)
1025=2n×205
2050=205n
n=2052050
n=10
Therefore, there are 10 terms in the arithmetic progression.