CUET UG 2025 — General Test Quantitative Reasoning

The problem requires finding the remainder $r$r when dividing $a$a by $b$b using the formula $a = bq + r$a=bq+r, where $q$q is the quotient and $r < b$r<b.

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For $a = 112, b = 7$a=112,b=7:

$112 \div 7 = 16$112÷7=16 with no remainder

$$112 = 7 \times 16 + 0$$112=7×16+0

Therefore $r = 0$r=0, which matches with (IV)

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For $a = 118, b = 9$a=118,b=9:

$$9 \times 13 = 117$$9×13=117

$$118 - 117 = 1$$118−117=1

$$118 = 9 \times 13 + 1$$118=9×13+1

Therefore $r = 1$r=1, which matches with (I)

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For $a = 119, b = 6$a=119,b=6:

$$6 \times 19 = 114$$6×19=114

$$119 - 114 = 5$$119−114=5

$$119 = 6 \times 19 + 5$$119=6×19+5

Therefore $r = 5$r=5, which matches with (III)

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For $a = 115, b = 8$a=115,b=8:

$$8 \times 14 = 112$$8×14=112

$$115 - 112 = 3$$115−112=3

$$115 = 8 \times 14 + 3$$115=8×14+3

Therefore $r = 3$r=3, which matches with (II)

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Final matching:

List-I	Remainder	List-II
(A) $a = 112, b = 7$a=112,b=7	$r = 0$r=0	(IV)
(B) $a = 118, b = 9$a=118,b=9	$r = 1$r=1	(I)
(C) $a = 119, b = 6$a=119,b=6	$r = 5$r=5	(III)
(D) $a = 115, b = 8$a=115,b=8	$r = 3$r=3	(II)

The correct answer is: (A) - (IV), (B) - (I), (C) - (III), (D) - (II)